45 min readNo calculatorNeeds: simultaneous equations, indices
By the end of this topic you should be able to
Find the nth term of an arithmetic progression
Find the sum of the first n terms of an arithmetic progression
Find the nth term and the sum of a geometric progression
Find the sum to infinity, and know the condition for it to exist
Use sigma notation
Sequences and the nth term
A sequence is an ordered list of numbers. A series is what you get when you add them up.
Two kinds appear on this syllabus, and telling them apart is the first thing to do in any question:
an arithmetic progression adds the same amount each time — the common differenced;
a geometric progression multiplies by the same amount each time — the common ratior.
To decide which you are looking at, take differences between consecutive terms. If they are all
equal it is arithmetic. If they are not, divide instead; if those are all equal it is geometric.
Arithmetic progressions
Here a is the first term and l is the last term. Use the second form of Sn when you already
know the last term, and the first form otherwise.
Two facts about a progression give you two equations, and a and d fall out of solving them
simultaneously. That is what almost every AP question is, underneath.
Geometric progressions
The two forms of Sn are the same expression with the top and bottom both multiplied by −1. Use
the left one when r<1 and the right one when r>1, purely to avoid negatives.
The sum to infinity
Add up a geometric progression forever and one of two things happens. If the terms are shrinking,
the total settles on a fixed number. If they are not, it grows without limit.
∣r∣<1 means −1<r<1: the ratio may be negative, but its size must be under 1. A progression
with r=−21 has a sum to infinity; one with r=−2 does not.
Sigma notation
r=1∑n means "add up, letting r run from 1 to n". So
r=1∑12(3r−2)=1+4+7+⋯+34
which is an arithmetic progression with a=1, d=3 and n=12, giving
S12=212[2+33]=210.
Counting the terms is where marks go. From r=1 to r=12 there are 12 terms; from r=5 to
r=12 there are 12−5+1=8.