Try each one on paper first, then check a single step. That is worth far more than reading a finished solution.
Example 1 — a modulus equation with two cases
Solve ∣2x−6∣=4.
- 1∣A∣=4 means A=4 or A=−4.The modulus discards the sign, so both possibilities must be considered.
- 2Case 1: 2x−6=4, so 2x=10 and x=5.
- 3Case 2: 2x−6=−4, so 2x=2 and x=1.
- 4Check x=5: ∣4∣=4 ✓
- 5Check x=1: ∣−4∣=4 ✓Both are valid, so there are two solutions.
Example 2 — two moduli, solved by squaring
Solve ∣x−3∣=∣2x+1∣.
- 1Both sides are non-negative, so squaring is safe and removes both moduli at once.∣A∣2=A2.
- 2(x−3)2=(2x+1)2
- 3x2−6x+9=4x2+4x+1Expand both sides fully.
- 40=3x2+10x−8Collect everything on one side.
- 5(3x−2)(x+4)=0, so x=32 or x=−4
- 6Check x=−4: ∣−7∣=7 and ∣−7∣=7 ✓And x=32 gives 37 on both sides ✓
Example 3 — a 'greater than' modulus inequality
Solve ∣x+1∣>3.
- 1∣A∣>k means A>k or A<−k.Two separate intervals — points further than 3 from zero.
- 2Case 1: x+1>3, so x>2.
- 3Case 2: x+1<−3, so x<−4.The inequality flips direction with the sign of the right side.
- 4Solution: x<−4 or x>2.This cannot be written as a single inequality — the values between are excluded.
- 5Check x=5: ∣6∣=6>3 ✓ and x=0: ∣1∣=1, not >3 ✓Testing one value inside and one outside confirms the direction.